If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
x = 0
x = 0
x = 0
x in (-oo:0) U (0:+oo)
(3*x^-1)/5+(6*x^-2)/5-1 = 0
3/5*x^-1+6/5*x^-2-1 = 0
t_1 = x^-1
6/5*t_1^2+3/5*t_1^1-1 = 0
6/5*t_1^2+3/5*t_1-1 = 0
DELTA = (3/5)^2-(-1*6/5*4)
DELTA = 129/25
DELTA > 0
t_1 = ((129/25)^(1/2)-3/5)/(6/5*2) or t_1 = (-(129/25)^(1/2)-3/5)/(6/5*2)
t_1 = 5/12*((129/25)^(1/2)-3/5) or t_1 = -5/12*((129/25)^(1/2)+3/5)
t_1 = -5/12*((129/25)^(1/2)+3/5)
x^-1-(-5/12*((129/25)^(1/2)+3/5)) = 0
x^-1+5/12*((129/25)^(1/2)+3/5) = 0
1*x^-1 = -(5/12*((129/25)^(1/2)+3/5)) // : 1
x^-1 = -5/12*((129/25)^(1/2)+3/5)
-1 < 0
1/(x^1) = -5/12*((129/25)^(1/2)+3/5) // * x^1
1 = -5/12*((129/25)^(1/2)+3/5)*x^1 // : -5/12*((129/25)^(1/2)+3/5)
-12/5*((129/25)^(1/2)+3/5)^-1 = x^1
x = -12/5*((129/25)^(1/2)+3/5)^-1
t_1 = 5/12*((129/25)^(1/2)-3/5)
x^-1-(5/12*((129/25)^(1/2)-3/5)) = 0
x^-1-5/12*((129/25)^(1/2)-3/5) = 0
1*x^-1 = -(-5/12*((129/25)^(1/2)-3/5)) // : 1
x^-1 = 5/12*((129/25)^(1/2)-3/5)
-1 < 0
1/(x^1) = 5/12*((129/25)^(1/2)-3/5) // * x^1
1 = 5/12*((129/25)^(1/2)-3/5)*x^1 // : 5/12*((129/25)^(1/2)-3/5)
12/5*((129/25)^(1/2)-3/5)^-1 = x^1
x = 12/5*((129/25)^(1/2)-3/5)^-1
x in { -12/5*((129/25)^(1/2)+3/5)^-1, 12/5*((129/25)^(1/2)-3/5)^-1 }
| 4n=2n+4 | | -12-7x+2x=-22 | | {4x}=4 | | 11x+3=10x+13 | | {4x}=4/4 | | 34=4m-2+2m | | 2x-1=-6x+5 | | -8m-9(610-685-30923m)=12 | | 15=16q+2 | | -165=-11x | | 3+7x-2x-(-8)-5x= | | 4x*7+n=44-n | | 46-3n=-25 | | 7r=-7/2 | | 8x+6-(-5x)=6 | | 6(7b+c-5a)-9(9-3c+6b)= | | 4x*7+n=n-44 | | -8+x=-18 | | 18=b-(-19) | | 8x+6-5x=6 | | p=2.4+2L | | 6=.60x | | (3x-5y)(3x-5y)= | | 32x^5-2x=0 | | n-(-3)=14 | | 30x^2-x-99=0 | | p=4.8+L | | 10r=-140 | | y=3x^2-27 | | 13+n=0 | | 3/4n-3=9 | | 15f-8f-13=-55 |